Two ropes of lengths 16m and 24m are to be cut into small pieces of equal lengths. What will be the maximum length of each piece?
Answers
Answered by
0
Answer:
take out there H.C.F by prime factorization so your answer is 8 m mate i think this type of question is suitable for only prime factorization
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Step-by-step explanation:
Answered by
5
Answer:
4m
Step-by-step explanation:
Maximum length of each piece = HCF of 16 & 20
16 = 2 *2 *2 *2
24= 2* 2* 2*3
So, HCF = 2*2*2=8
So, length of each piece = 8 m
Step-by-step explanation:
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