two ropes, one 24 m long and other 26 m long,are to be cut in to pieces of same length.what will be the maximum possible length of each piece
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1
So for finding this we should find these number'so hcf (highest common fctor)
2 [24 26]
2 [12 13]
•°•hcf=2×2
=4
So the maximum possible length of each piece is 4m
2 [24 26]
2 [12 13]
•°•hcf=2×2
=4
So the maximum possible length of each piece is 4m
Answered by
2
find HCF of 24 and26 then find common factor among them then from that find biggestnumber that number will be the possible length of each piece
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