Question

Two runners starting together run on a circular path 6 and 8 minutes, respectively, to complete one round.How many minutes later do they meet again for the first time on the start line assuming constant speed

Answer 1

Answer:

24 minutes later

Step-by-step explanation:

They will meet on the start line at an LCM of the individual time taken = 24

First person would have covered 4 rounds while the second would have covered 3 rounds of the circumference

Answer 2

Answer:

logic behind the answer is here.

Step-by-step explanation:

Let A covers 2пr in 6 mins.

=> 1 min=2пr/6 unit covers

Let B covers it in 8 mins.

It's lagging A by 2 mins so when B reaches the starting point A would have completed 8/3пr units.( coz 2 mins extra i.e 2пr + 2/3 пr).

So B lags 2/3 пr units than A in each of it round completions.

So only after 3 rounds B will compensate the 2/3пr lags.( coz 2/3 ×3 =2)

Given speed of A and B are constant .And the lagging one (B ) has to meet ( A).

Hence , 8×3=24.

Answer is 24 mins.