Question

Two same center circle,larger circle's is 25cm.And that circle's 48cm long chord touches small circle. Then find radius of small circle.​

Answer 1

Answer:

According to question,

Chord AB = 48 cm

OA = 25 cm (given)

OC is perpendicular to AB

Now, AC = CB = 48/2cm =24 cm

In right-angled ∆ OCA,

OC² + CA² = OA² (Pythagoras Theorem)

=> OC² = OA²-CA²

=> OC² = (25)²-(24)²

=> OC² = 625-576

=> OC² = 49

=> OC = 7cm

Ans) Radius of Inner Circle is 7cm