Question

Two samples of water, a and b have ph values of 4.4 and 6.4 respectively. how many times more acidic is sample a than sample b ?

Answer 1

Answer

Sample A is 100 times more acidic than sample B

Explanation:

pH of A = 4.4 = -Log(H+) = 10^-4.4

pH of B = 6.4 = -Log(H+) = 10^-6.4

pH A/pH B = 10^-4.4/10^-6.4 = 100

ph of A = 100 x pH of B

Answer 2

Answer:

Concept:

Properties of acids and bases

Explanation:

$\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right] \left[\mathrm{H}^{+}\right] \rightarrow concentration in moles/litre\\For sample A\\ 4.4=-\log \left[\mathrm{H}^{+}\right] \\ \left[\mathrm{H}^{+}\right]=3.98 \times 10^{-5} \mathrm{moles} / litre\\For sample B\\ 6.4=-\log \left[\mathrm{H}^{+}\right] \\ \left[\mathrm{H}^{+}\right] =3.98 \times 10^{-7} moles / litre$

$\therefore \quad \frac{\left[\mathrm{H}^{+}\right] \text {of sample } A}{\left[\mathrm{H}^{+}\right] \text {of sample } \mathrm{B}}=100$

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