Two satellites A and B of the same mass are orbiting the earth at altitudes R and 3R respectively, where R is the radius of the earth. Taking their orbit to be circular abtain the ratios of their kinetic and potential energies.
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Given:
Mass of satellites A and B is same
Altitude of A's orbit from earth = R
Altitude of B's orbit from earth = 3R
To find:
Ratios of A's and B's respective kinetic and potential energies
Answer:
- Let mass of satellites of A and B = m and the mass of earth = M
- We know that, the kinetic energy in the orbit = Half its gravitational energy
- Kinetic energy of A = GMm/[2×(2R)²]. -(1)
- Kinetic energy of B = GMm/[2×(4R)²] -(2)
- The ratio of kinetic energies of A to B = equation (1)/(2) = 4
- Potential energy of each satellite = mgH
- Potential energy of A = mg(2R). -(3)
- Potential energy of B = mg(4R). -(4)
- The ratio of potential energies of A to B = equation (3)/(4) = 2
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