Question

Two separate bulbs contain ideal gas A and B. The density of A is twice

that of B.The molecular mass of A is half that of B. If the two gases are at

the same temperature, the ratio of pressure of A to that of B is:

(a) 2 (b) 1/2 (c) 4 (d) ¼


please give the correct answer otherwise your answer will be reported❤❤❤❤​

Answer 1

To find density :-

PM = DRT

∴ D =$\frac{PM}{RT}$

Given :-

$D_1 =2D_2 ∣ M_1 = \frac{1}{2} M_2 ∣ T_1 =T_2$

$\frac{D_1}{D_2} =2 ∣ \frac{M_1}{M_2} = \frac{1}{2}$

Now D=PM (∵ R&T are constant)

${D_1}{D_2}= \frac{P_1M_1}{P_2M_2}\\\\2 = \frac{P_1}{P_2} × \frac{1}{2}\\\\2×2 = \frac{P_1}{P_2}\\\\∴ \frac{P_1}{P_2} =4$

Answer 2

Answer:

C) 4

Explanation:

To find density :-

PM=DRT

∴D=

RT

PM

Given :-

D

1

=2D

2

∣ M

1

=

2

1

M

2

∣ T

1

=T

2

D

2

D

1

=2 ∣

M

2

M

1

=

2

1

Now D=PM (∵R&T are constant)

D

2

D

1

=

P

2

M

2

P

1

M

1

2=

P

2

P

1

×

2

1

2×2=

P

2

P

1

∴

P

2

P

1

=4

HOPE IT HELPS:)