Two separte bulbs contain ideal gases A and B . The density of A is twice as that of gas B . The molecular mass of gas A is half as that of B . If two gases are at same temperature , the ratio of the pressure of A to that of B is
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Density of the gas =Pressure×MolecularmassRT=Pressure×MolecularmassRT
d=PMRTd=PMRT
dAdB=2dAdB=2
=PA×MAPB×MB=PA×MAPB×MB
=PAPB×12=PAPB×12
∴PAPB=4∴PAPB=4
Hence the ratio is 4:1
Density of the gas =Pressure×MolecularmassRT=Pressure×MolecularmassRT
d=PMRTd=PMRT
dAdB=2dAdB=2
=PA×MAPB×MB=PA×MAPB×MB
=PAPB×12=PAPB×12
∴PAPB=4∴PAPB=4
Hence the ratio is 4:1
Anonymous:
this is not understandable
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Density of gas = Pressure×Molecular massRTd=PMRTit is given dAdB=2=PM×MAPB×MB=PAPB×12hence,PAPB=4
partial pressure se aage he
Wo to aese hai Pt = P1 +P2+ P3+........ Pn
lo g choro
general gas equation me
universal gas equation me
Yeah wo to aese hai :- PV = nRT
ahre yar densities wala topic hoga
apki federal ki book he na
no
Jhut bolne ka bhi limit hota he kattti
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