Question

Two sets of quantum numbers with
the Same number of radial nodes are :

(A) n = 3;1=0; ml=0 and n=2;1=0; ml= 0
(B) n= 3;1=1; ml=1 and n=2;1=1; ml=0
(C) n= 3;1=2; ml=0 and n=2;1=1; ml=0
(D) n=3;1=1; ml=-1 and n=2;1=1; ml=0​

Answer 1

Answer:

I think the answer is d

make me brain list

Answer 2

Answer:

Set of quantum number $n= 3;l=2; m_{l}=0$ and $n=2;l=1; m_{l}=0$ have same number of radial nodes, which is equal to zero.

Therefore option (C) is correct.

Explanation:

We can use formula to find the number of radial nodes $=n-l-1$

where $n$ is principle quantum number

 and $l$ is azimuthal quantum number

• For  n = 3; l=0; ml=0

            Number of radial nodes $=n-l-1=3-0-1=2$

       For n=2; l=0; ml= 0

              Number of radial nodes $=n-l-1=2-0-1=1$

•  For n=3; l=1; ml= 1

              Number of radial nodes $=n-l-1=3-1-1=1$

          For n=2; l=1; ml= 0

              Number of radial nodes $=n-l-1=2-1-1=0$

•  For n=3; l=2; ml= 0

              Number of radial nodes $=n-l-1=3-2-1=0$

        For n=2; l=1; ml= 0

              Number of radial nodes $=n-l-1=2-1-1=0$

•  For n=3; l=1; ml= -1

              Number of radial nodes $=n-l-1=3-1-1=1$

         For n=2; l=1; ml= 0      

               Number of radial nodes $=n-l-1=2-1-1=0$