Question

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30° and 45° respectively. If the lighthouse is 100 m high, the distance between the two ships ?

Answer 1

Answer:

I'm really sorry I don't know this concept

Answer 2

Step-by-step explanation:

Let AB be the lighthouse and C and D be the positions of the ships.

Then, AB = 100 m, 

ACB = 30° and 

ADB = 45°.

AB/AC = tan 30° =1/root 3

AC = AB x root 3 = 100(root 3) m.

AB/AD = tan 45° = 1    

AD = AB = 100 m.

CD = (AC + AD)= (100(root 3)+ 100) m

= 100(root 3 + 1)

= (100 x 2.73) m

= 273 m.

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