Two ships are sailing on opposite sides of a Lighthouse 150 M high and in the same line of of the foot of the Lighthouse find the distance between the ships when the angle of depression of the ships are observed from the top of Lighthouse are 60 degree and 45 degree
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AB= Height of lighthouse= 150m
At C and D there are two ships.
Angle ADB = 45°
therefore, tan45°=AB/BD
AB=BD
therfore, BD=150m
Angle ACB = 60°
therefore, tan60°=AB/BC
root3=150/BC
BC = 150/root3
BC = 50×root3
= 86.6m
Therfore distance between the ship is
BC+BD=150+86.6
=236.6m
At C and D there are two ships.
Angle ADB = 45°
therefore, tan45°=AB/BD
AB=BD
therfore, BD=150m
Angle ACB = 60°
therefore, tan60°=AB/BC
root3=150/BC
BC = 150/root3
BC = 50×root3
= 86.6m
Therfore distance between the ship is
BC+BD=150+86.6
=236.6m
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