Question

Two ships are there in the Sea on either side of a lighthouse in such a way that the ship and the light house are in the same straight line. The angles of depression of two ships as observed from the top of the light house are 60degree &45degree. If the height of the light house is 200m , find the distances between two ships

Answer 1

in triangle ABC
tan 60= ac/BC

√3=200/BC

√3bc=200. 1

in triangle ACD

tan 45 = ac/CD

1=200/CD
CD=200


bd =√3bc+200

bd=200√3+200

bd=200(√3+1)

Answer 2

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