Two ships P and Q,leave the harbour O simultaneously. P travels at 25km/h due North. Q at 30km/h on a bearing of 120°. Find the distance P Q and the bearing of Q from P four hours later.
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distance covered by P = 25×4=100
_______--------------Q. = 30×4= 120
Distance between them = √( distance of P)^2 + (D of Q)
√[(100)^2 +(120)^2]
= √(10000 +14400)
=√( 24400)
=156.2 Km
Q is in South East direction of P.
_______--------------Q. = 30×4= 120
Distance between them = √( distance of P)^2 + (D of Q)
√[(100)^2 +(120)^2]
= √(10000 +14400)
=√( 24400)
=156.2 Km
Q is in South East direction of P.
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