Physics, asked by keethan8298, 1 year ago

Two shm y1=asin(wt) , y2=acos(wt) are superimposed on particle

Answers

Answered by ritesh5496
8

Resultant wave is given by

Y=Y1+Y2

Y=A( sinwt + cotwt)

Y=A[sin(wt) + sin(90+wt)]

Y=A[ 2sin((2wt +90)/2)cos(90/2)]

Y=A[√2sin(wt + 45)]

Y= √2Asin(wt + 45)

SO total energy E = (½ )mw²(√2A)²=

m(wA)².

hope it clears.

Answered by fluffy46
2

Answer:

Y=Y1+Y2

Y=A( sinwt + cotwt)

Y=A[sin(wt) + sin(90+wt)]

Y=A[ 2sin((2wt +90)/2)cos(90/2)]

Y=A[√2sin(wt + 45)]

Y= √2Asin(wt + 45)

SO total energy E = (½ )mw²(√2A)²=

m(wA)².

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