Question

Two short bar magnets of length 1cm each have magnetic moments 1.20Am², and 1. 00Am² , respectively . They are placed on a horizantal table parallel to each other with their N poles pointing towards the south.they have a common magnet equator and are separated by a distance of 20.0cm. The value of the resultant horizantal magnetic induction at the mid - point O of the line joining their centres is close to (Horizantal component of the earth's magnetic induction is 3.6× 10⁻⁵wb/m² [Jee mains 2013] ​

Answer 1

Answer:

The value of the resultant horizantal magnetic induction at their centres is close to 2.5×10⁻⁵wb/m²

Explanation:

Given :- Distance between two short bar magnets r = 1cm

Magnetic moment , M₁ = 1.2 Am²

M₂ = 1Am²

Magnetic induction Bₕ = 3.6× 10⁻⁵wb/m²

∵ Net magnetic field ,Bnet = B₁ + B₂ + Bₕ

Bnet = μ₀ (M₁ +M₂ )/4πr³ + Bₕ

Bnet = 10⁻⁷ ( 1.2+1)/(0.1)³ + 3.6 × 10⁻⁵

= 2.56 × 10⁻⁴ Wb/m²Answer

Answer 2

Answer:

A particle of charge -16× 10⁻¹⁸C moving with velocity 10ms⁻¹ along the x-axis entres a region where a magnetic field of induction B is along the y-axis and an electric field of magnetitude 10⁴ Vm⁻¹ is along the negative z-axis . If the charged particle continues moving along x-axis , the magnitude of B is [AIEEE 2003]