Question

Two short electric dipoles are placed as shown. the energy of electric interaction between these dipoles will be

Answer 1

If the two electric dipoles are placed together energy of electric interaction between these two dipoles will be equal

Answer 2

Answer:

The energy of electric interaction between the dipoles will be V=$\bold{-\frac{2 P_{1} P_{2}}{4 \pi \varepsilon r^{3}}}$

Explanation:

Let one of the dipoles is $P_{1}$ and the other dipole is  $P_{2}$.

The value of the dipole is calculated on the basis of the charge exhibited, and the charges are considered to be point charge.

Similarly the potential of the dipoles is calculated as:

The energy of the dipole is given as

V=$\bold{-\frac{2 P_{1} P_{2}}{4 \pi \varepsilon r^{3}}}$

Where “r” is the radius and the negative sign tells about the repulsion property of the charges.