Two sides AB and BC of ∆ABC are 28cm and 38cm respectively. Find the length of the side AC, if the perimeter of ∆ABC is 100 cm.
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Perimeter of triangle
=a+b+c
100 cm=28+38+x
100cm=66+x
x=100-66
x=44 cm
Therefore the third side of the triangle ABC is 44cm
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