Math, asked by anirbanchanda804, 4 months ago

two sides AD and BC of a cyclic quadrilateral be extended to meet a P. If angle APB=60° and angle ABC=40° find angle BAD.​

Answers

Answered by CrazyStars
1

Answer:

Given:

AD and BC intersect each other at point P, this gives a triangle APB. Angle APB= 60° and angle ABC= 40°.

TO FIND:

Angle BAD or angle BAP(as D is a point on line AP)

Step-by-step explanation:

In ️APB,

Angle APB= 60°......(i)

Angle ABP=40°.......(ii)

To find angle BAP, we can use angle sum property of a triangle.

Here ,

angle ABP + angle ABP + angle BAP= 180°

=40° + 60° + angle BAP = 180°

=100° +angle BAP = 180°

=angle BAP = 180° - 100

=angle BAP = 80°

Therefore, length of Angle BAP or angle BAD = 80°

Answered by itZzAnshu
0

Question :

Two sides AD and BC of a cyclic quadrilateral be extended to meet a P. If angle APB = 60° and angle ABC = 40°, find angle BAD.

Given :

AD and BC intersect each other at point P, this gives a triangle APB. Angle APB = 60° and angle ABC = 40°.

To find :

Angle BAD or angle BAP(as D is a point on line AP)

Solution :

In ️APB,

Angle APB= 60°......(i)

Angle ABP=40°.......(ii)

To find angle BAP, we can use angle sum property of a triangle.

Here ,

angle ABP + angle ABP + angle BAP= 180°

=》40° + 60° + angle BAP = 180°

=》100° +angle BAP = 180°

=》angle BAP = 180° - 100

=》angle BAP = 80°

Therefore, length of Angle BAP or angle BAD = 80°

Additional Information :

Cyclic quadrilateral is that type of quadrilateral in which all vertices lie on circle and the sum of angles of opposite angle of cyclic quadrilateral is 180° .

Thank you.

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