two sides AD and BC of a cyclic quadrilateral be extended to meet a P. If angle APB=60° and angle ABC=40° find angle BAD.
Answers
Answer:
Given:
AD and BC intersect each other at point P, this gives a triangle APB. Angle APB= 60° and angle ABC= 40°.
TO FIND:
Angle BAD or angle BAP(as D is a point on line AP)
Step-by-step explanation:
In ️APB,
Angle APB= 60°......(i)
Angle ABP=40°.......(ii)
To find angle BAP, we can use angle sum property of a triangle.
Here ,
angle ABP + angle ABP + angle BAP= 180°
=》40° + 60° + angle BAP = 180°
=》100° +angle BAP = 180°
=》angle BAP = 180° - 100
=》angle BAP = 80°
Therefore, length of Angle BAP or angle BAD = 80°
Question :
Two sides AD and BC of a cyclic quadrilateral be extended to meet a P. If angle APB = 60° and angle ABC = 40°, find angle BAD.
Given :
AD and BC intersect each other at point P, this gives a triangle APB. Angle APB = 60° and angle ABC = 40°.
To find :
Angle BAD or angle BAP(as D is a point on line AP)
Solution :
In ️APB,
Angle APB= 60°......(i)
Angle ABP=40°.......(ii)
To find angle BAP, we can use angle sum property of a triangle.
Here ,
angle ABP + angle ABP + angle BAP= 180°
=》40° + 60° + angle BAP = 180°
=》100° +angle BAP = 180°
=》angle BAP = 180° - 100
=》angle BAP = 80°
Therefore, length of Angle BAP or angle BAD = 80°
Additional Information :
Cyclic quadrilateral is that type of quadrilateral in which all vertices lie on circle and the sum of angles of opposite angle of cyclic quadrilateral is 180° .