Question

Two sides of a rectangle differ by 3.5cm. Find the dimensions of the
rectangle if its perimeter is 67cm. Solve the problem by using
Cramer’s Rule.

Answer 1

$\huge\underline\blue{\textbf{Required Answer :-}}$

$\huge\underline\pink{\textbf{Given :-}}$

Two sides of the rectangle differ by 3.5 cm. [Condition 1.]

Perimeter of the rectangle = 67 cm. [Condition 2.]

$\huge\underline\green{\textbf{To find :-}}$

• Dimensions of the rectangle.

$\huge\underline\red{\textbf{Solution :-}}$

Let the length of the rectangle be 'x' cm and width be 'y' cm.

$\underline\blue{\textbf{According to the first condition :-}}$

x - y = 3.5 cm _____ Eq. 1.

$\underline\pink{\textbf{According to the second condition :-}}$

Perimeter = 67 cm _____ Eq. 2.

We know, Perimeter = 2(Length + Breadth)

: ⟹ 2(x + y) = 67 cm

: ⟹ x + y = ${\frac{67}{2}}$

: ⟹ x + y = 33.5 cm _____ Eq. 3.

$\underline\green{\textbf{By Carmer's Rule :-}}$

x - y = 3.5

x + y = 33.5

Refer to the attachment for solving procedure...

$\underline\pink{\textbf{Required Dimensions are :-}}$

Length = 18.5 cm.

Width = 15 cm.

$\huge\underline\purple{\textbf{Hope it helps...}}$

Answer 2

Answer:

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