Question

Two sides of a right angled triangular field are equal if length of each of them is 45m,find the area of the field alsa,find the hypotenuse

Answer 1

Area:4050m2

hypoten use=63.64m appr,

Answer 2

$\huge\sf\pink{Answer}$

☞ Area of field = 1012.5 &

☞ Hypotenuse = 63.63 (Approx)

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ Two sides of a right angled-triangular field are equal.

✭ Length of each of them is 45m

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

◈ The area and the Hypothenuse?

$\rule{110}1$

$\huge\sf\purple{Steps}$

$\sf\star\: Diagram \: \star$

$\setlength{\unitlength}{1.5cm}\begin{picture}(6,2)\linethickness{0.5mm}\put(7.7,2.9){\large\sf{C}}\put(7.7,1){\large\sf{B}}\put(10.6,1){\large\sf{A}}\put(8,1){\line(1,0){2.5}}\put(8,1){\line(0,2){1.9}}\qbezier(10.5,1)(10,1.4)(8,2.9)\put(7.1,2){\sf{\large{45 m}}}\put(9,0.7){\sf{\large{45 m}}}\put(8.2,1){\line(0,1){0.2}}\put(8,1.2){\line(3,0){0.2}}\end{picture}$

Area of triangle is given by,

➝ $\sf\dfrac{1}{2}× base × height$

➝ $\sf\dfrac{1}{2} × 45m × 45m$

➝ $\sf\dfrac{1}{2} × 2025$

➝ $\sf\red{1012.5 m^2}$

Using pythagoras theorem

»» AC² = AB² + BC²

»» AC² = 45² + 45²

»» AC² = 2025 + 2025

»» AC² = 4050

»» AC = √4050

»» $\sf\orange{AC = 63.63 (Approx)}$

$\rule{170}3$