Math, asked by sukhveerkaur137, 4 months ago

Two sides of a right triangle measure 222 units and 444 units.

2\text{ units}2 units4\text{ units}4 units
What is the area of the square that shares a side with the third side of the triangle?​

Answers

Answered by amitnrw
5

Given : Two sides of a right triangle measure 2 units and 4  units.

To Find : area of the square that shares a side with the third side of the triangle  ​

Solution:

Case 1 : If  Two sides of a right triangle measure 2 units and 4  units.

if sides are perpendicular sides

Then using Pythagorean theorem

third side² = 2² + 4²

=> third side² = 4 + 16

=>  third side² = 20

area of the square that shares a side with the third side of the triangle =  third side² = 20 sq units

Case 2 : If   4  units is hypotenuse side

Then using Pythagorean theorem

third side² = 4² - 2²

=> third side² = 16 - 4

=>  third side² = 12

area of the square that shares a side with the third side of the triangle =  third side² = 12 sq units

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Answered by equestrian999
0

Answer:

20 units^2

Step-by-step explanation:

We can use the Pythagorean theorem to find the area of the square for the third side.

The equation for the Pythagorean theorem is

a^2 + b^2 = c^2a

2

+b

2

=c

2

a, squared, plus, b, squared, equals, c, squared

where aaa and b are the lengths of the two legs of the triangle, and c is the length of the hypotenuse.

Hint #22 / 3

In this case, a = 2, b = 4a=2,b=4a, equals, 2, comma, b, equals, 4, and c = xc=xc, equals, x.

\begin{aligned} a^2 + b^2 &= c^2 \\\\ 2^2 +4^2&= \blueD{ x^2}\\\\ 4 + 16 & =\blueD{ x^2} \\\\ \blueD{20} & = \blueD{x^2} \\\\ \end{aligned}

a

2

+b

2

2

2

+4

2

4+16

20

 

=c

2

=x

2

=x

2

=x

2

The area of the square for the third side of the triangle is 20 units^2

squared.

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