two sides of a triangle are 10 centimetre and 5 cm in length and the length of the median to the third side is 6.5 CM if the area of the triangle is 6 root p CM square find the value of p
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Given
two sides of a triangle are 10 centimetre and 5 cm in length and the length of the median to the third side is 6.5 CM if the area of the triangle is 6 root p CM square find the value of p
- By inserting a line we get
- Length of median = 1/2 √2 b^2 + 2 c^2 – a^2
- 6.5 / 0.5 = √2 x 5^2 + 2 x 10^2 – a^2
- Squaring both sides we get
- 42.25 / 0.25 = 50 + 200 – a^2
- 169 = 250 – a^2
- a ^2 = 250 – 169
- a^2 = 81
- So a = 9
- We know that S = a + b + c / 2
- = 10 + 5 + 9 / 2
- = 24 / 2
- = 12
- Now area of triangle = √ s(s – a) (s – b) (s – c) = 6√p
- = √12(12 – 10) (12 – 5) (12 – 9)
- = √12 x 2 x 7 x 3
- = √36 x 2 x 7
- = 6 √14 = 6√p
- Now p = 14
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