Question

Two sides of a triangle are 10cm and 12cm. The perimeter of the triangle is 35cm. What will be the length of the third sid​

Answer 1

Answer:

9.5 cm

Step-by-step explanation:

A=hbb

2

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forhb

hb=﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2

2b=﹣354+4·353·10+4·353·12﹣4·(35·10)2﹣12·352·10·12﹣4·(35·12)2+8·35·102·12+8·35·10·122

2·12