Question

Two sides of a triangle are 16 cm and 14 cm,
respectively. The length of the altitude to the
longer side is 10 cm. Find a) area of A and b)
the length of the altitude to the other side.​

Answer 1

Answer: The other side length is 4✓6+2✓26 cm

Step-by-step explanation: follow the attachment

#ANSWERWITHQUALITY. #BAL

Answer 2

area of triangle = 80  cm²

length of the altitude to the other side. is 11.42 cm

Step-by-step explanation:

Two sides of a triangle are 16 cm and 14 cm,

length of the altitude of side 16 cm = 10 cm

then base = 16 cm

height = 10 cm

area of triangle = $\frac{1}{2} \times base\times height$

area = $\frac{1}{2} \times 16\times 10$

area = 8× 10 = 80 cm²

now area = 80 cm²

base = 14 cm

we need to find the length of the altitude of base 14 cm

then

area =  $\frac{1}{2} \times base\times height$

$80 = \frac{1}{2}\times 14 \times height$

$height = \frac{80\times 2}{14}$

height = 11.42 cm

hence ,

area of triangle = 80  cm²

length of the altitude to the other side. is 11.42 cm

#Learn more:

the area of trapezium is 78 CM. its altitude is 16 cm and one of the parallel sides is 10 cm longer than the other find the length of parallel sides

https://brainly.in/question/5753237