Question

Two sides of a triangle are 18 cm and 10 cm and the perimeter is 42 cm. What will be the area of the triangle?​

Answer 1

$\huge\sf\green{Answer:-}$

● Perimeter = 42cm

● Side A= 18cm

● Side B = 10cm

● Side C = ?

Perimeter of triangle = a + b + c

42 = 18 + 10 + c

42 = 28 + c

c = 42 - 28

c = 14

C = 14cm

☆Semi perimeter =

S = (a + b + c) = 42/2 = 21cm

$\sf\underline\red{Using\:Heron's\:formula:-\:}$

☆Area of triangle=

$= \sqrt{s(s - a)(s - b)(s - c)}$

$= \sqrt{21(21 - 18)(21 - 10)(21 - 14)}$

$= 21 \sqrt{11cm^{2} }$

Area of triangle = 21√11cm² or (69.65cm²)

Step-by-step explanation:

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