Two sides of a triangle are 2x-y=0 and x+y=3. If its centroid is (2,3), what is its third side?
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Given:
Two sides of a triangle are 2x-y=0 and x+y=3. If its centroid is (2,3)
To find:
What is its third side?
Solution:
From given, we have:
Let the third side be: y = mx + c
the other two sides are y=2x and x+y=3.
Therefore, one vertex is:(1,2)
The other two vertices are: [c/(2-m), 2c/(2-m)] & [(3-c)/(m+1), (3m+c((m+1)].
We get,
c/(2-m) + (3-c)/(m+1) + 1 = 6
2c/(2-m) + (3m+c)/(m+1) + 2 = 9.
upon solving the above equations, we get,
c = -9 and m = 5.
The third side is y = 5x - 9.
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