two sides of a triangle are 5 cm and 13 cm and its perimeter is 30 cm the area of the traiangle is
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Solve for area
A=30cm²
a Side
5
cm
b Base
13
cm
P Perimeter
30
cm
Using the formulas
A=s(s﹣a)(s﹣b)(s﹣c)
P=a+b+c
s=a+b+c
2
Solving forA
A=1
4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1
4·﹣304+4·303·5+4·303·13﹣4·(30·5)2﹣12·302·5·13﹣4·(30·13)2+8·30·52·13+8·30·5·132=30cm²
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