Question

Two sides of a triangle are 6.4 m and 4.8 m. If height of the triangle corresponding to 4.8 m side is 6 m

find:

(I) area of the triangle

(II) height of the triangle corresponding to 6.4 m side,​

Answer 1

Diagram:

⇑ Attached picture :)

Question:

Two sides of a triangle are 6.4 m and 4.8 m. If height of the triangle corresponding to 4.8 m side is 6 m

find:

(1) area of the triangle

(2) height of the triangle corresponding to 6.4 m side.

To find :

• Area of triangle
• Height of triangle corresponding to 6.4 m

Given:

• 1 side of triangle = 4.8m
• 2 side of triangle = 6.4 m
• Height corresponding to side 4.8= 6m

Answer :

$\pink{ \fbox{ \text{part 1}}}$

To find area of triangle:

We know:

$\sf \: Area \: of \: triangle = \dfrac{1}{2} \times base \times height$

So equation to find area will form as follows:

$: \implies\sf \: Area \: of \: triangle = \dfrac{1}{2} \times BC \times AD$

$: \implies\sf \: Area \: of \: triangle = \dfrac{1}{2} \times 4.8 \: m\times 6 \: m$

$: \implies\sf \: Area \: of \: triangle = \dfrac{288}{20} {m}^{2}$

$: \implies \star \boxed{\sf\: Area \: of \: triangle = 14.4 {m}^{2} }\star$

$\pink{ \fbox{ \text{part 2}}}$

To find Height of triangle corresponding to 6.4 m:

We can find height by using formula of Area

$\sf \: Area \: of \: triangle = \dfrac{1}{2} \times base \times height$

$:\implies \sf \: Area \: of \: triangle = \dfrac{1}{2} \times AC \times BO$

$:\implies \sf \: 1.44 = \dfrac{1}{2} \times 6.4 \times BO$

$:\implies\sf BO = \dfrac{1.44 }{3.2}$

$: \implies \star \boxed{\sf\: BO = 4.5\:m }\star$

Answer 2

Answer:

(i) area of the triangle;

(ii) height of the triangle corresponding to

6.4 m side

5. The base and the height of a triangle are in