Question

Two sides of a triangle are 8 cm and 12 cm and its perimeter is 32 cm . Find the area of the triangle​

Answer 1

Answer:

16√8

Step-by-step explanation:

side 1= 8cm

side 2= 12cm

perimeter= 32cm

p= S1+S2+S3

32= 8+12+S3

32-20= s3

12= side 3

Area= √s(s-a)(s-b)(s-c)

s= 8+12+12/2 = 16cm

a=8cm, b=12cm, c=12cm

A= √16(16-8)(16-12)(16-12)

= √16×8×4×4

= 4×4 × 4×2 × 4 ×4

=4×4√4×2 = 16√8

Hope it helps...Thank u ☺️