Physics, asked by archufx, 9 months ago

Two sides of a triangle are given by 2i^+3j^+2k^and -3i^+2j^+k^,then area of triangle is

Answers

Answered by shanthipraba72
6

Answer:7.65 un.sq.  Am I right friend?

Explanation:The given 2 sides are in vector form. so u can use vector method. u can find the area of the triangle by vector product method and the formula is

                     area of triangle=1/2 |A(vector product)B|

 where A=2i^+3j^+2k^

B=-3i^+2j^+k^,

                  |   i^   J^   k^  |

                  |   2   3    2    |

                  |  -3   2    1     |

  =(3-4)i^-(2+6)j^+(4+9)k^

=-1i^-8j^+13k^                |A*B|=[(-1)^2+(-8)^2+(13^2)]^1/2

=[1+64+169]^1/2  =15.30

Area=1/2*15.30 = 7.65 un. sq

Similar questions