Two sides of a triangle are given by 2i^+3j^+2k^and -3i^+2j^+k^,then area of triangle is
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Answer:7.65 un.sq. Am I right friend?
Explanation:The given 2 sides are in vector form. so u can use vector method. u can find the area of the triangle by vector product method and the formula is
area of triangle=1/2 |A(vector product)B|
where A=2i^+3j^+2k^
B=-3i^+2j^+k^,
| i^ J^ k^ |
| 2 3 2 |
| -3 2 1 |
=(3-4)i^-(2+6)j^+(4+9)k^
=-1i^-8j^+13k^ |A*B|=[(-1)^2+(-8)^2+(13^2)]^1/2
=[1+64+169]^1/2 =15.30
Area=1/2*15.30 = 7.65 un. sq
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