Question

Two sides of a triangle are given by 2i^+3j^+2k^ and −3i^+2j^+k^, then area of triangle is

Answer 1

${\bold{\huge{\green{\textbf{Answer}}}}}$

Given:

2î +3j +2k and -3î+ 2j+k

${\bold{\red{Area \: of \: triangle} \rightarrow \frac{1}{2}× base× height}}$

$\rightarrow{ \frac{1}{2}×( 2î +3j +2k)×(-3î+ 2j+k)}$

${\frac{1}{2}× (-6î+6j+2k)}$

${-3î+3j+ k}$