Question

Two sides of a triangular field are 112m and 50m. Then find the height of the altitude on the side of 78 m length if perimeter of the triangle is 240m

Answer 1

Answer:

First we have to find the area of the triangle using Heron's formula

$\sqrt{s \: (s - a)(s - b)(s - c)}$

So, on putting the values accordingly we get the area as 1680m2

Formula for area of a triangle is also 1/2 ×base ×height

So putting the values....

1680 = 1/2 × 78 × height

height(altitude) = 43.08 m

Step-by-step explanation:

Hope this helps you......

Answer 2

Answer:

$sides =112m,50m and 78m$

$perimeter=240m$

Step-by-step explanation:

by using heron's formula

$s = a+b+c/2$

$= 112+50+78/2$

$=240/2$

$=120 m$

$area= \sqrt{s(s-a)(s-b)(s-c)}$

$=\sqrt{120(120-112)(120-50)(120-78)}$

$=\sqrt{120*8*70*42}$

$=1680 m^{2}$

height of the altitude $=1/2*b*h$

$1680=1/2*78*h$

$1680=39*h$

$h=1680/39$

$h=43.07m$

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