Question

Two sides of a triangular field measures 8 m each. If the third side of the field measures 7 m,
then how much wire is required for fencing the boundary of the given field? Also, find the cost
of fencing, if the cost of wire is 13 per metre.​

Answer 1

Answer:

Step-by-step explanation:

perimetre =8+8+7=23 m  or.23*13=rs 299

Answer 2

GiVeN :-

• Two equal sides of triangle = 8m

• One unequal side = 7m

• Cost of Fencing = ₹ 13 / metre

To FiNd :-

• Length of wire required for fencing

• Cost of fencing of wire

SoLuTiOn :-

Now,

Two sides are equal.

Hence the given triangle is Isosceles Triangle.

Now,

Length of Wire = Perimeter of triangle

Perimeter of Triangle = 8 + 8 + 7 = 23m

So

Length of Wire = 23 m

Cost of Fencing = 23 × 13 = 299 Rs.