two sides of parallelogram are in the ratio 43 if its perimeter is 56 cm find the length of its side
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let the two side before 4X and 3X
then 4X+3X=56
7X=56
X=56/7=8
1st side=4X =4*8=32
2nd side=3X=3*8=24
then 4X+3X=56
7X=56
X=56/7=8
1st side=4X =4*8=32
2nd side=3X=3*8=24
mansi83:
i think moharana shubham ur ans. is wrong
Answered by
1
perimeter of parallelogram = 2(l+b)
let the lenght nd breadth be = 4x and 3x
perimrter of parallelogram =2( 4x+ 3x)
56. = 2(7x)
56. = 14x
x = 56/ 14
x= 4
length of parallelogram = 4x = 4×4=16
breadth ofcparallelogram = 3x=3×3= 12
hence , the lenght of parallelogram is 16
hope it helps
let the lenght nd breadth be = 4x and 3x
perimrter of parallelogram =2( 4x+ 3x)
56. = 2(7x)
56. = 14x
x = 56/ 14
x= 4
length of parallelogram = 4x = 4×4=16
breadth ofcparallelogram = 3x=3×3= 12
hence , the lenght of parallelogram is 16
hope it helps
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