Question

Two sides of the parallelogram PQRS are 9 cm and 6 cm.
The height corresponding to the base PQ is 4 cm. Find :
(a) Area of the parallelogram
(b) The height corresponding to the base PS.​

Answer 1

area of parallelogram = b × h

                 9 × 4 = 36 cm²

height corresponding PS =

6 (corresponding base) × h = 36

h = 36 ÷ 6

h = 6 cm

Answer 2

a) The area of the parallelogram is 36. sq. cm

b) The height corresponding to the base PS.​

Explanation:

Area of parallelogram = Side x ( corresponding altitude)

Given : Two sides of the parallelogram PQRS are 9 cm and 6 cm.

i.e. PQ= RS = 9 cm

and QR = PS = 4 cm

The height corresponding to the base PQ is 4 cm.

(a) Area of the parallelogram = PQ  x (corresponding height)

= 9 x 4 = 36 sq. cm

The area of the parallelogram is 36. sq. cm.

(b) Let h be the height corresponding to the base PS.​

Then, h x PS  = Area of the parallelogram

⇒ h x 6 = 36 sq. cm

⇒ h= 6 cm

Hence , the height corresponding to the base PS.​

# Learn more :

In a parallelogram pqrs the altitude corresponding to side PQ and PS are respectively 7 cm and 8 cm find the psif PQ is 10 cm

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