Question

two sides of the quadrilateral are in the ratio of 2:3 find them​

Answer 1

Answer:

Answer

Let the angles of the quadrilateral in degrees be =2a,3a,4a and a

Since the sum of angles of a quadrilateral =360

o

,

2a+3a+4a+a=360

o

10a=360

o

a=36

So,

the angles of the quadrilateral are =2a=72

o

,3a=108

o

,4a=144

o

and

a=36

Suppose

∠A=72

o

and ∠B=108

o

Sum of ∠A and ∠B=72

o

+108

o

=180

o

This means, AB is a transversal to the parallel sides AD and BC as the sum of

interior angles on the same side of transversal is 180

o

Hence, AD∥BC and ABCD is a trapezium

Answer 2

Answer:

answer is in attachment