Question

two sides of triangle are 120cm,170cm,and its perimeter is 540 cm find its area​

Answer 1

Answer:

9000 cm ²

Step-by-step

let third side be x

perimeter of a triangle= sum of all its sides

540=120+170+x

540=290+x

540-290=x

250=x

area of triangle(by using heron's formula)= $\sqrt{} s(s-a)(s-b)(s-c)$

s=perimeter/2

s=270

Area=sqrt(square root) of 270 (270-120)(270-170)(270-250)

Area=sqrt 270x150x100x20

Area=sqrt 81 x 10^6 cm²

area=9000 cm²

 

Answer 2

Answer:

9,000cm²

Step-by-step explanation:

Measurement of Side 1 = 120cm

Measurement of Side 2 = 170cm

Perimeter of the triangle = 540cm

So , third side

= 540cm - 120cm - 170cm

= 250cm

Finding area , using Heron's formula :—

$s \: = \frac{a + b +c }{2} \\ s \: = 270cm$

$a = \sqrt{s(s - a)(s - b)( s-c )} = \\ = \sqrt{270cm(270cm - 120cm)(270cm - 170cm)( 270cm-250cm )} = \\ = \sqrt{270cm \times 150cm \times 100cm \times 20cm} \\ = \sqrt{270cm \times 300000 {cm}^{3} } \\ = \sqrt{81000000 {cm}^{4} } \\ = 9000 {cm}^{2}$