Question

Two sides of triangle are 88 and 114 m. Perimeter of traingle is 320. Find the area of triangle

Answer 1

$\huge\underline\mathfrak{Answer}$

3642.62${m}^{2}$



$\huge\underline\mathfrak{Solution}$

$\huge\underline\mathfrak{Formula}$

.if side of a triangle are a,b,c

perimeter of a triangle =a+b+c

$area \: \: of \: a \: triangle = \sqrt{s(s - a)(s - b)(s - c)}$

a,b,c are side of a triangle
$s = \frac{a + b + c}{2}$



$\textbf{Step-By-Step-Solution}$



GIVEN



$\textbf{Step.1}$

Perimeter= 320

a= 88,b=144,c=x°

=>x°=320-(88+144)

x°=320-232

x°=88



$\textbf{Step.2}$

$s = \frac{a + b + c}{2}$

$s = \frac{88 + 88 + 144}{2}$

$s = 160$

$area \: \: of \: a \: triangle = \sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{160(160 - 88)(1 60 - 144)(160 - 88)}$

$\sqrt{160 \times 72 \times 16 \times 72}$

$\sqrt{160 \times 72 \times 16 \times 72}$

$72 \times 4 \sqrt{16 \times 10}$

$72 \times 4 \times 4 \sqrt{10}$

$1152 \sqrt{10}$

1152×3.16

$3642.62 {m}^{2}$