Physics, asked by vidyapraveen2006, 6 months ago

Two similar charges of the same magnitude q are placed at a distance d apart . The intensity of the electric field at a point midway between the charges is _________. Also represent the above sum diagrammatically.

Answers

Answered by dipikamallikudp
2

Answer:

electrons.

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Answered by vaibhavsemwal
1

Answer:

Two similar charges of the same magnitude q are placed at a distance d apart. Then, the intensity of the electric field at a point midway between the charges is zero.

Explanation:

Consider the diagram shown below,

Let two similar charge has magnitude q

and are kept 2r distance apart.

Then, distance of midpoint from each charge =  r.

Intensity of electric field is given by the formula, E=\frac{1}{4 \pi \epsilon_o} \frac{q}{r^2}

where, q is magnitude of charge,

\epsilon_0 is the permittivity of free space,

r is the distance at which electric field is to be found.

electric field at midpoint due to charge A = E_A=\frac{1}{4 \pi \epsilon_o} \frac{q}{r^2}       [toward right]

electric field at midpoint due to charge B = E_B=\frac{1}{4 \pi \epsilon_o} \frac{q}{r^2}       [towards left]

Electric field at midpoint due to A and B are of same magnitude and are in opposite direction.

So, net intensity of electric field at midpoint = E_A-E_B =\frac{1}{4 \pi \epsilon_o} \frac{q}{r^2}-\frac{1}{4 \pi \epsilon_o} \frac{q}{r^2}=0

So, net intensity of electric field at midpoint is zero.

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