Two similar conducting spheres having charges –3 μC the +5 μC are connected by a conducting wire for a short while, then
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3.125 × 1013 electrons will flow from negatively charged sphere to positively charged sphere
2.5 × 1013 electrons will flow from positively charged sphere to negatively charged sphere
Final charge on each sphere will be +1 μC each
Both (2) and (3)
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Answer:
Final charge on each sphere will be +1 μC each
Explanation:
(1) q = q1 + q2 = – 3 μC + 5 μC = 2 μC
This 2 μC charge will divide equally between the sphere the 1 μC each.
(2) 4 μC coulomb charge will flow
⇒ Number of electron (n)
4x10^-6/1.6x10^-19 = 2.5 × 1013
From negatively charged sphere to positively charged sphere.
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refer to the attachment
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