Question

Two similar cones having their volumes are 12π and 96π.if csa of the smaller cone is 15π .Find csa of larger cone​

Answer 1

Answer:

since the cones are similar so l₁/l₂ = r₁/r₂

the the volumes are v₁ 12π unit³ , v₂ = 96π unit³

so curved surface area = 15π unit²

so v₂/v₁ = 96π/12π

(πr₁²l₁)/(πr₂²l₂) = 8 cancelling 3

⇒ (r₂²l₂)/(r₁²l₁) = 8

⇒ (\frac{r^2_2}{r^2_1})^2*\frac{l_2}{l_1}=8(

r

1

2

r

2

2

)

2

∗

l

1

l

2

=8

⇒ r₂³/r₁³ = 8 using l₁/l₂ = r₁/r₂

⇒ r₂/r₁ = 2

so curved surface area of the unknown cone be x

so cs₂/cs₁ = x/15π

⇒ πr₂l₂/πr₁l₁ = x/15π

⇒ r₂/r₁ x l₂/l₁ = x/15π

⇒ r₂²/r₁² = x/15π using r₂³/r₁³ = 8

⇒ 4 = x/15π

⇒ x = 60π ANSWER

Answer 2

Answer:

Math Spte

Answer:

since the cones are similar so Wes/ the the volumes are v, 12n unit, v-96T unit so curves surface area - 15 unita

SO V/V, 9614120

fract2_22_192" frac(L2/L1)-81

cancelling 3

ir =8 using Wish

1,, -2

so curved surfece area of the unknown cone be

SD Cscs, x/1S

11, x lh - x/15