Two similar cylindrical tins have base radii 4cm and 7cm. If the capacity of smaller tin is 230 cm3, find the capacity of larger tin
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Given:
- Radius of similar cylinderical tin = 4cm and 7cm
- Capacity of smaller tin = 230cm³
Find:
- Capacity of larger tin.
Solution:
Let, the radius of larger tin "R" cm
and radius of smaller tin "r" cm
Height of both cylinder are same "h" cm
Now, we know that
↣ Volume of Cylinder = πr²h
So,
¤ (Volume of smaller Cylinder)/(Volume of larger cylinder) = πr²h/πR²h
¤ V₁/V₂ = πr²h/πR²h
where,
- V₁ = 230cm³
- r = 4cm
- R = 7cm
♛ Substituting these values ♛
↦V₁/V₂ = πr²h/πR²h
↦230/V₂ = π(4)²h/π(7)²h
↦230/V₂ = (4)²/(7)²
↦230/V₂ = 16/49
• Cross - multiplication •
↦ 16V₂ = 230 × 49
↦ 16V₂ = 11270
↦ V₂ = 11270/16
↦ V₂ = 704.375cm³
Hence, capacity of larger cylindrical tin will be 704.375cm³
Anonymous:
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