two similar equal charges are found to repel each other with a force of 16 Newton when placed what will be the force between them if the space between them is filled with substance of dielectric constant 8?
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Answered by
68
Heya!!
Since Force = k. Q1*Q2 / d^2
Since charges r equal then Q1 = Q2.
=) 16 = 9* 10^9 * Q^2 / (0.3)^2
=) 16 * 0.3*0.3 / 9*10^9 = Q^2
=) 16 * 10^-11 = Q^2
=) 1.26 * 10^-5 C = Q
Charge is either in + or -.
When dielectric constant is 8, then F = 16/8 = 2 N.
Hope it helps uh!!
Since Force = k. Q1*Q2 / d^2
Since charges r equal then Q1 = Q2.
=) 16 = 9* 10^9 * Q^2 / (0.3)^2
=) 16 * 0.3*0.3 / 9*10^9 = Q^2
=) 16 * 10^-11 = Q^2
=) 1.26 * 10^-5 C = Q
Charge is either in + or -.
When dielectric constant is 8, then F = 16/8 = 2 N.
Hope it helps uh!!
YashrajGupta1:
hi
Answered by
62
F=16N,
d=0.3m,
q1=q2=q
when air is replaced with a substance of dielectric constant k the force between the charges will be,
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