Two similar point charges q, and q2 are placed at a distancer,
apart in air. The force between them is F1. A dielectric slab of
thickness t(<r) and dielectric constant K is placed between
the charges. Then, the force between the same charges is F2-
The ratio F1/F2 is:
(a) 1
(b) K
r-t++ VK
(c)
(d)
r-t+tK
2
2
r
Cr-eteve
r
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Answer:
I think the answer is option (c)....
Explanation:
Look the attachment.....
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