Question

Two Similar triangles as their areas in the
ratio 9:16. find the ratio of their corresponding
perimeters​

Answer 1

$\huge\bold\pink{Answer}$

The ratio of areas of two similar triangles having areas A1 and A, respectively is given by

$A1/A2=(S1/S2) 2\\9/16=(S1/S2) 2$

Taking square roots on both sides, we get

Si/S2=3/4

The ratio of their corresponding sides will be 3:4.

Answer 2

Answer:

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Step-by-step explanation: