Question

Two similar triangles have areas 144 CM square and 81 cm square respectively. If the perimeter of the smaller triangle is 16 cm. Find the perimeter of the Other Triangle.

Answer 1

I hope this answer will helpful for you

Answer 2

e$\frac{a1}{a2} = \frac{ {p1}^{2} }{ {p2}^{2} }$

$\frac{144}{81} = \frac{p1 {}^{2} }{ {16}^{2} }$

P1 = 64/3