Two similar wires of same length and cross sectional area
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krishtiwari07
Secondary School Physics 13+7 pts
Two wires of equal length and cross-section area suspended as shown in figure. Their Young's modulus are Y 1 and Y 2 respectively. The equivalent Young's modulus will be
(A) Y 1 + Y 2 (B) Y1+Y22 (C) Y1Y2Y1+Y2 (D) ?Y1Y2
Report by Awesomeraghav9946 03.12.2018
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krishtiwari07
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Qwpenguin Ace
As there is no figure attached, it can't be answered properly but here I'm putting some generalised steps which may help u.
Young's modulus (Y) = (F/A) / (L/ΔL) = FL / AΔL
As the two wires have same length and cross section area,
Y₁ = F₁L / AΔL₁
or, L/A = Y₁ΔL₁ / F₁
and; Y₂ = F₂L / AΔL₂
or, L/A = Y₂ΔL₂ / F₂
Therefore,
Y₁ΔL₁ / F₁ = Y₂ΔL₂ / F₂
Now here, put the values of force acting on both the strings and the relation between Y₁ and Y₂ can be deducted.