Math, asked by begumanees222, 6 months ago

Two similiar cones have volumes 121 cu. units and 96t cu units. If
the curved surface area of the smaller cone is 1571 sq. units, what is
the curved surface area of the larger one?​

Answers

Answered by Anonymous
4

Answer:

Let R = radius of base and L = lateral height, H = height of cone. curved surface or lateral surface = A = π R L , and volume = V = π/3* R² H, Similar cones have the same (cone) angle at the apex. Hence the same ratios among R, H and L.

Step-by-step explanation:

Answered by gargivyadav2919
2

Step-by-step explanation:

Small cone volume ⇒

3

1

πr

1

2

h

1

=12π

Large cone volume ⇒

3

1

πr

2

2

h

2

=96π

[Similar cones

r

2

r

1

=

h

2

h

1

]

3

1

πr

2

2

h

2

3

1

πr

1

2

h

1

=

96π

12π

r

2

2

r

1

2

=

8

1

×

h

1

h

2

[

h

1

h

2

=

r

2

r

2

]

r

2

2

r

1

2

=

8

1

×

r

1

r

2

⇒r

1

3

=8r

2

3

⇒r

1

=2r

2

Given surface area of smaller cone ⇒πr

1

r

1

2

+h

2

+πr

1

2

=15π

Large cone =πr

2

2

+πr

2

r

2

2

+h

2

2

=π(2r

1

)

2

+π(2r

1

)

(2r

1

)

2

+(2h

1

)

2

⇒4πr

1

2

+π2r

1

×2

r

1

2

+h

1

2

⇒4(πr

1

2

+πr

1

r

1

2

+h

1

2

)=4×15π

⇒60π.

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