Question

Two simple pendula of length L and 4L are pulled aside to the right and are at rest so that they make an angle 30 °with the vertical. They are then released simultaneously at time t =0 the time after which they will be in phase is
the vertical. They are then released simultaneously at time 0 The time after which they will be in phase is
(B)
(C) 2 V! (D) ſi
2
(A)​

Answer 1

Answer:

Two simple pendulums A and B having lengths l and l/4 respectively, are released from the position as shown in fig. Calculate the time (in seconds) after which, the two strings becomes parallel for the first time.

(Take l=

π

2

90

m and g=10 m/s

2

)θ

1

=θ

2

Length of a simple pendulum is 2m and mass of its bob is 2kg if the tension in the string exceeds 100N, it will break. If g=10ms

2

and the bob is whirled in a horizontal plane, the maximum angle through which the sting can make vertical during rotation is

I hope it's help you

Answer 2

Answer:

answer is 4π √L/g

Explanation:

I have written in short cut , just for simplicity ....

I have used time formula and wave equation combination gave the answer ...

thank you