Question

Two simple pendulums are in two different places. The length of the second pendulum is 0.4 times the
length of the first pendulum, and the acceleration of gravity experienced by the second pendulum is 0.9
times the acceleration of gravity experienced by the first pendulum. Determine the comparison
of the frequency of the first pendulum to the second pendulum.
Given T = 2n Take g=9.8m/s​

Answer 1

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